Question
Download Solution PDFLet {En} be a sequence of subsets of \(\mathbb{R}\).
Define
\(\limsup _n E_n=\bigcap_{k=1}^{\infty} \bigcup_{n=k}^{\infty} E_n\)
\(\liminf _n E_n=\bigcup_{k=1}^{\infty} \bigcap_{n=k}^{\infty} E_n\)
Which of the following statements is true?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept -
(i) If the sequence xn convergent then limsupn En = liminfn En
Calculation:
Let {En} be a sequence of subsets of R
\(\limsup _n E_n=\bigcap_{k=1}^{\infty} \bigcup_{n=k}^{\infty} E_n\) and
\(\liminf _n E_n=\bigcup_{k=1}^{\infty} \bigcap_{n=k}^{\infty} E_n\)
for option 1, if convergent then limsupn En = liminfn En
option 1 is incorrect
x \(∈\) \(\ {\cap}\) Ai imply x ∈ Ai
x \(∈\)\(\ {\cap}\)(\(\ {\cup}\)En )
x \(∈\)\(\ {\cup}\) En ( finite )
Hence option (2) & (4) are incorrect
Hence option (3) is correct
Last updated on Jun 5, 2025
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