In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, first order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.374, cos 22° = 0.927)

Question

Question

In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, first order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.374, cos 22° = 0.927)

0.0745 nm
0.0137 nm
0.745 nm
0.135 nm

Answer 1

Concept:

Bragg’s Law states that when an X-ray beam are allowed to scatter through a crystalline surface, its angle of incidence θ will reflect with some angle of scattering θ. And when the path difference d is equal to a whole number n, of wavelength.

It can be represented as

2dsinθ =nλ

Calculation:

Given:

d = 0.18 nm, n = 1, θ = 22°

From Bragg’s law:

2d sin θ = nλ

2 × 0.18 × sin 22° = 1 ⋅ λ

λ = 0.13464 nm

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Question

In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, first order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.374, cos 22° = 0.927)

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