In the following network potential at ‘O’

F1 S.Y 13.4.20 Pallavi D9

  1. 4 V
  2. 3 V
  3. 6 V
  4. 4.8 V

Answer (Detailed Solution Below)

Option 4 : 4.8 V
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CUET General Awareness (Ancient Indian History - I)
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10 Questions 50 Marks 12 Mins

Detailed Solution

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CONCEPT:

  • According to Ohm’s law: The potential difference across a resistor in a circuit is directly proportional to the current flowing in it.

V = R I

Where V is potential difference, R is resistance and I is current.

  • Kirchhoff’s current law (KCL): It states that, the total current entering a circuit’s junction is exactly equal to the total current leaving the same junction.

EXPLANATION:

F1 S.Y 13.4.20 Pallavi D9

Let potential at O is V’ and all the current is originating from the point O.

According to the KCL, the sum of all the current originating from the point O will be equal to zero.

Use Ohm’s law to final total current originating from O:

Current in OA + Current in OB + Current in OC = 0

(V – 8)/2 + (V – 4)/4 + (V – 2)/2 = 0

(2 V – 16 + V – 4 + 2 V – 4)/ 4= 0

5 V – 24 = 0

Potential at O (V) = 24/5 = 4.8 Volt
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