Question
Download Solution PDFIn a self locking brake, the force required to apply the brake is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
When the frictional force is great enough to apply the brake with no external force, then the brake is said to be a self-locking brake.
The figure shows the brake drum.
From the equilibrium of forces,
F × l + μRN × b = RN × a
F × l = RN × a - μRN × b
RN (a - μb) = F × l
\(R_N=\frac{Fl}{(a-μ b)}\)...........................(1)
Braking torque on Drum is given as, TB = Ff × R ⇒ TB=μRN × R
\(\therefore T_B=μ\times \frac{Fl}{(a-μ b}\times R\)
For self-locking brake:
From equation (1), the expression for the force "F" required to apply the brake is obtained as, \(F=\frac{R_N(a-μ b)}{l}\)
And if a < μ b, then F will be negative or zero. This means that no external force is required to apply the brake and hence the brake is self-locking.
Self-energizing brakes
When the frictional force helps the applied force in applying the brake, such types of brakes is said to be self-energizing brakes.
The brake should be self-energizing and not the self-locking.
Last updated on Mar 27, 2025
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