In a 3-phase induction motor, the maximum torque under standstill occurs when the rotor resistance (R2) is:

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MPPGCL JE Electrical 19 March 2019 Shift 2 Official Paper
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  1. equal to leakage reactance (X1 + X2)
  2. greater than leakage reactance (X1 + X2)
  3. less than leakage reactance (X1 + X2)
  4. almost equal to X1 - X2

Answer (Detailed Solution Below)

Option 1 : equal to leakage reactance (X1 + X2)
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Detailed Solution

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Torque in the 3-phase induction motor

The torque of a 3-phase induction motor is given by:

\(T={3\over ω_s}{V^2\over ({R_2\over s}^2)+X_2^2}{R_2\over s}\)

where, V = Supply

ωs = Synchronous speed in radian/sec

R2 = Rotor resistance

X2 = Rotor reactance

s = Slip

Condition for maximum torque

The maximum torque of a 3-phase induction motor occurs at:

\(s={R_2\over X_1+X_2}\)

If the maximum torque has to occur in starting, the value of the slip (s)=1

\(1={R_2\over X_1+X_2}\)

\(R_2=X_1+X_2\)

The maximum torque of a 3ϕ induction motor occurs when rotor resistance is equal to leakage reactance (X1 + X2).

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