If y = \(\rm\left(\frac{1}{x}\right)^x \), then value of \(\rm e^e\left(\frac{d^2 y}{d x^2}\right)_{x=e}\) is:

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CUET Mathematics 30th Aug 2022 Official Paper
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  1. 2 − \(\rm\frac{1}{e}\)
  2. 4 − \(\rm\frac{1}{e}\)
  3. \(\rm\frac{1}{e}\)
  4. 1 − \(\rm\frac{1}{e}\)

Answer (Detailed Solution Below)

Option 2 : 4 − \(\rm\frac{1}{e}\)
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Detailed Solution

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Calculation:

y = (1/x )x

take log on both sides

log y = x log(1/x)

log y = x(log 1 - log x)

log y = x(-log x)

Differentiate with respect to y

1/y × dy/dx = -( 1 + log x)

dy/dx = -(1/x)x(1 + log x)

again Differentiate with respect to x .

d2y/dx2 = -(dy/dx(1 + logx) +y(1/x)

d2y/dx2 = -(-(1/x)x(1+ log x)2 + (1/x)x+1)

\(\rm e^e\left(\frac{d^2 y}{d x^2}\right)_{x=e}\) = 4 -1/e

Hence, option 2 is correct.

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