If the centre-to-centre distance between meshing gears is 150 mm and the velocity ratio is 2 : 1, what will be the pitch diameter of the pinion and gear?

Question

Question

This question was previously asked in

ISRO SHAR Technician B Fitter 29 April 2018 Official Paper

Answer 1

Given: r1 + r2 = 150 mm

\(\frac{N_1}{N_2}=2\)

For gear in mesh:

D1 + D2 = T1 + T2

T1 + T2 = 2(r1 + r2) = 300

\(\frac{N_1}{N_2}=\frac{T_2}{T_1}=\frac{D_2}{D_1}=2 \Rightarrow D_2=2D_1\)

D1 + D2 = 3D1 = 300

D1 = 100 mm

D2 = 200 mm