Question
Download Solution PDFIf P(A) = 0.4, P(B) = 0.8 and P(B|A) = 0.6, then P(A ∪ B) is equal to:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For two events A and B:
- P(A ∪ B) = P(A) + P(B) - P(A ∩ B).
- The conditional probability of B given A is defined as:
P(B|A) = \(\rm \dfrac{P(A\cap B)}{P(A)}\), when P(A) > 0
Calculation:
Using the relation P(B|A) = \(\rm \dfrac{P(A\cap B)}{P(A)}\), we get:
0.6 = \(\rm \dfrac{P(A\cap B)}{0.4}\)
⇒ P(A ∩ B) = 0.24
Now using the relation P(A ∪ B) = P(A) + P(B) - P(A ∩ B), we get:
P(A ∪ B) = 0.4 + 0.8 - 0.24 = 0.96.
Last updated on Jun 20, 2025
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