If 1 + tan2 x - 2 tan x = 0, then find the value of x.

  1. \(\rm\frac{\pi}{3}\)
  2. \(\rm\frac{\pi}{4}\)
  3. \(\rm\frac{\pi}{6}\)
  4. \(\rm\frac{\pi}{12}\)

Answer (Detailed Solution Below)

Option 2 : \(\rm\frac{\pi}{4}\)
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Detailed Solution

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Concept:

Trigonometry:

  • tan \(\rm\frac{\pi}{4}\) = 1.


Algebra:

  • (a ± b)2 = a2 ± 2ab + b2.


Calculation:

1 + tan2 x - 2 tan x = 0

⇒ 12 - 2 (1) (tan x) + (tan x)2 = 0

⇒ (1 - tan x)2 = 0

⇒ 1 - tan x = 0

⇒ tan x = 1

⇒ x = \(\rm\frac{\pi}{4}\).

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