निम्नलिखित प्रश्नों में ‘?’ के स्थान पर लगभग क्या मान आना चाहिए?

33\(\frac{1}{3}\) ÷ 150 × 80 + ? = 32\(\frac{7}{9}\)

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RRB Clerk Prelims Memory Based Paper (Held On: 17 August 2024 Shift 2)
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  1. 15
  2. 20
  3. 25
  4. 40
  5. 50

Answer (Detailed Solution Below)

Option 1 : 15
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गणना:

33\(\frac{1}{3}\) ÷ 150 × 80 + ? = 32\(\frac{7}{9}\)

⇒ 100/3 ÷ 150 × 80 + ? = 295/9

100/3 × 1/150 × 80 + ? = 295/9

2/3 × 1/3 × 80 + ? = 295/9

160/9 + ? = 295/9

? = 295/9 - 160/9

? = 135/9 = 15

विकल्प 1 सही उत्तर है।

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