Question
Download Solution PDFएक रेखा का चुंबकीय दिक्मान 135° 30' है। यदि अवनति 5° 15'W है तो वास्तविक दिक्मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
TB (वास्तविक दिक्मान) = MB (चुंबकीय दिक्मान) ± अवनति
(पूर्व के लिए + ve और पश्चिम अवनति के लिए – ve)
गणना:
दिया गया है,
दिक्मान = 5° 15' W
रेखा का चुंबकीय दिक्मान = 135° 30'
TB (वास्तविक दिक्मान) = MB (चुंबकीय दिक्मान) - अवनति
वास्तविक दिक्मान = 135° 30' - 5° 15'
वास्तविक दिक्मान = 130° 15'
Last updated on May 28, 2025
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