Question
Download Solution PDFयदि a2 + b2 + c2 - ab - bc - ca = 0 है, तो a ∶ b ∶ c है :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है :
a2 + b2 + c2 - ab - bc - ca = 0
हल :
यहाँ हमारे पास 3 चर और केवल एक समीकरण है।
टिप्पणी: इस प्रकार के प्रश्नों को हल करने के लिए हम किन्हीं भी 2 चरों का मान लेते हैं।
माना कि b = 1 और c = 1
⇒ a2 + 1 + 1 - a - 1 - a = 0
⇒ a2 + 1 - 2a = 0
⇒ ( a - 1 )2 = 0 [ ∵ ( A + B )2 = A2 + B2 + 2AB ]
अब a = 1
अब हमारे पास है, a = 1, b = 1 और c = 1
इसलिए a : b : c = 1 : 1 : 1
अतः, सही उत्तर "1 : 1 : 1" है।
Last updated on Jun 13, 2025
->HSSC CET Application Deadline 2025 has been extended. The last date to apply online is 14th June till 11:59 PM.
->Earlier, Haryana CET Group C Notice for EWS Certificate was out. A valid format of EWS Certificate has been given in the Notice.
-> Haryana CET Group C Notification 2025 was out on 26th May 2025.
-> The HSSC CET Registration 2025 is open from 28th May to 14th June 2025.
-> The minimum educational qualification to apply for the Common Eligibility Test is 10+2/equivalent
-> Candidate applying for CET should not be less than 18 years of age and not more than 42 years.
-> Aspirants must go through the Haryana CET Previous Years’ Papers to understand the need for the exam and prepare for the exam in the right direction.