Question
Download Solution PDFयदि 2sin(3x -15)° = 1 है, जहाँ 0° < (3x - 15) < 90° है, तो cos2(2x +15)° + cot2 (x + 15)° का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
2sin(3x -15)° = 1
गणना:
sin(3x - 15)° = 1/2
⇒ sin (3x - 15)° = sin 30°
⇒ (3x - 15)° = 30°
⇒ 3x = 30° + 15° = 45°
⇒ x =
तब,
cos2(2x +15)° + cot2 (x +15)°
cos2(2 × 15 +15)° + cot2 (15 +15)°
⇒ cos2(45)° + cot2(30)°
⇒
⇒
∴ cos2(2x +15)° + cot2 (x +15)° =
Last updated on Jun 13, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.