Question
Download Solution PDFY-अक्ष पर एक बिंदु के निर्देशांक ज्ञात कीजिए जो बिंदु P(1, -2, 1) से 3√3 की दूरी पर है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
दो बिंदुओं P(x1, x2, x3) और Q(y1, y2, y3) के बीच की दूरी निम्न द्वारा दी गई है
\(PQ=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\)
गणना:
मान लीजिए बिंदु A(0, y, 0) है। तब,
AP = 3√3
\(⇒ \sqrt{(0-1)^2+(y+2)^2+(0-1)^2}=3\sqrt3\)
दोनों पक्षों का वर्ग करने पर, हम प्राप्त करते हैं
1 + (y + 2)2 + 1 = 27
⇒ (y + 2)2 = 25
⇒ y + 2 = ±5
⇒ y = 3, -7
अत: अभीष्ट बिंदु के निर्देशांक (0, 3, 0) और (0, -7, 0) हैं।
Last updated on May 31, 2025
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