For an electron in 1s orbital of He+, the average value of r, (r) is

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CSIR-UGC (NET) Chemical Science: Held on (26 Nov 2020)
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  1. \(\rm \frac{3}{2}a_0\)
  2. \(\rm \frac{3}{4}a_0\)
  3. 3a0
  4. \(\rm \frac{1}{2}a_0\)

Answer (Detailed Solution Below)

Option 2 : \(\rm \frac{3}{4}a_0\)
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Detailed Solution

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Concept:

  • The average value in Quantum Mechanics is the average result obtained when a large number of measurements are made on identical systems or systems in the same state.
  • For an observable quantity A, the average value or expectation value is given by,

\(\left\langle {\rm{A}} \right\rangle {\rm{ = }}\int {{{\rm{\Psi }}^{\rm{*}}}{\rm{A\Psi d\tau }}} \)

Explanation:

  • The normalized ground state wave function for a one-electron system like an H atom (He+) is:

\({\Psi _{1s}} = N{e^{ - {r \over {Z{a_ \circ }}}}}\)  where, N is the normalization constant and Z is the atomic number of the nuclei.

  • The average value or expectation value of r is given by,

\(\left\langle r \right\rangle = \int {{\Psi ^ * }_nr{\Psi _n}} d\tau \)

  • Now, for an electron in 1s orbital of He+, the average value of r, (r) is given by,

\(\left\langle r \right\rangle = \int {{\Psi ^ * }_{1s}r{\Psi _{1s}}} d\tau \), where \(d\tau = {r^2}dr\sin \theta d\theta d\phi \)

\( = N\int_0^ \propto {r3{e^{ - {{2r} \over {Z{a_ \circ }}}}}} dr\int_0^\pi {sin\theta d\theta } \int_0^{2\pi } {d\phi } \)

\( = {{3{a_ \circ }} \over {2Z}}\)

  • Now, for the He+ ion the atomic number

(Z) = 2.

  • Thus, the average value of r, \(\left\langle r \right\rangle \)  for He+ ion is

​\( = {3 \over 4}{a_ \circ }\).

Conclusion:

Hence, for an electron in 1s orbital of He+, the average value of r, (r) is \({3 \over 4}{a_ \circ }\)

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