Fixed end moment of a propped cantilever due to a concentrated load P at a distance ‘a’ form fixed ends as shown in figure is given by

F3 Savita Engineering 10-8-22 D1

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  1. \(\rm \frac{{Pab\left( {L + b} \right)}}{{2{L^2}}}\)
  2. \(\rm \frac{{Pab\left( {L + b} \right)}}{{{L^2}}}\)
  3. \(\rm \frac{{ - Pab\left( {L + b} \right)}}{{2{L^2}}}\)
  4. \(\rm \frac{{ - Pab\left( {L + a} \right)}}{{{L^2}}}\)

Answer (Detailed Solution Below)

Option 3 : \(\rm \frac{{ - Pab\left( {L + b} \right)}}{{2{L^2}}}\)
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महाराष्ट्र राजपत्रित तांत्रिक सेवा मराठी: व्याकरण क्विज
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Explanation:

F3 Savita Engineering 10-8-22 D2

 

F3 Savita Engineering 10-8-22 D3

fixed end moments

Fixed end

\(M_{FAB}= \frac{{Pab(L + b)}}{{2{L^2}}}\)

So \(M_{FAB} = \frac{-{Pab(L + b)}}{{2{L^2}}}\)

Negative sign as anticlockwise rotation is taken

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