Question
Download Solution PDFFind the value of K for which equation x – Ky = 2, 3x + 2y = 5 has unique solution.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Consider expression: a1x + b1y + c = 0 and a2x + b2y + c = 0
Condition for the system has unique solution if a1/a2 ≠ b1/b2
Condition for the system has infinite solution if a1/a2 = b1/b2 = c1/c2
Condition for the system has no solution if a1/a2 = b1/b2 ≠ c1/c2
Calculation:
The equation is x – Ky = 2, 3x + 2y = 5
Here, a1 = 1, b1 = -k, a2 = 3, b2 = 2
1/3 ≠ -k/2
k ≠ -2/3
∴ The required value of K should not be equal to -2/3
Last updated on Aug 9, 2024
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