Find the remainder when we divide 3x4 - 2x2 + 4x - 1 by 2x - 1.

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SSC CGL 2022 Tier-I Official Paper (Held On : 07 Dec 2022 Shift 4)
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Answer (Detailed Solution Below)

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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
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Detailed Solution

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Calculation:

 3x4 - 2x2 + 4x - 1 is divisible by 2x – 1 

For finding the required remainder put

2x – 1 = 0 ⇒ x = 1/2

Required remainder

 3(1/2)4 - 2(1/2)2 + 4(1/2) - 1

⇒ 3/16 - 1/2 + 2 -1

⇒ 3/16 + 1/2 = 11/16

∴ The remainder is 11/16.

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