Consumption of 2300 W energy in 1 hour is measured with 230 revolutions of meter disc in an energy meter. Calculate the meter constant.

This question was previously asked in
MPPGCL JE Electrical 28 April 2023 Shift 2 Official Paper
View all MPPGCL Junior Engineer Papers >
  1. 1 rev/kWh
  2. 10 rev/kWh
  3. 1000 rev/kWh
  4. 100 rev/kWh

Answer (Detailed Solution Below)

Option 4 : 100 rev/kWh
Free
MPPGCL JE Electrical Full Test 1
100 Qs. 100 Marks 120 Mins

Detailed Solution

Download Solution PDF

Concept

The number of revolutions made by the energy meter per kilowatt-hour is known as the meter constant of an energy meter.

It is represented by k.

The energy consumed in time 't' is given by:

For t = 1 hr

where, V = Voltage

I = Current 

cosϕ = Power factor

Calculation

Given, Power consumption = 2300 W = 2.3 kW

Time = 1 hour

Energy consumed = 2.3 kWh

Number of revolutions = 230

k = 100 rev/kWh

Latest MPPGCL Junior Engineer Updates

Last updated on May 29, 2025

-> MPPGCL Junior Engineer result PDF has been released at the offiical website.

-> The MPPGCL Junior Engineer Exam Date has been announced.

-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.

-> Candidates can apply online from 23rd December 2024 to 24th January 2025.

-> The selection process includes a Computer Based Test and Document Verification.

-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.

Hot Links: teen patti gold real cash teen patti real cash apk teen patti casino apk