A transistor connector in CE configuration has a V_CC of +12 V and R_C = 1 kΩ. Identify the coordinates of the load line from the given options.

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ALP CBT 2 Electronic Mechanic Previous Paper: Held on 21 Jan 2019 Shift 1

Answer 1

In common-emitter (CE) configuration, load line is drawn for I_C and V_CE.

F2 S.B 15.9.20 Pallavi D 2

So, the coordinates of the load line will be:

A = (V_cc, 0) ≡ (+12 V, 0 mA)

\(B = \left( {0,\frac{{{V_{cc}}}}{{{R_c}}}} \right) = \left( {0,\;12\;mA} \right)\)

Here,

\(\frac{{{V_{cc}}}}{{{R_c}}} = \frac{{ + 12\;V}}{{1\;k{\rm{\Omega }}}} = \frac{{12\;V}}{{1 \times {{10}^3}{\rm{\Omega }}}}\)

\(= 12 \times {10^{ - 3}}\;A\)

Since, 1 × 10^-3 = 1 milli, we can write:

12 × 10^-3 A = 12 mA