Question
Download Solution PDFA train having a certain length of x m covers the two different platforms having lengths of 140 m and 180 m in 18 sec and 20 sec, respectively. Find speed of train (in kmph).
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFAs it covers the platform having lengths of 140 m in 18 sec.
So,
\(18=\frac{x+140}{s}\\ \Rightarrow s= \frac{x+140}{18}---(i)\)
As it covers a platofrm of length180 m in 20 sec.
So,
\(20=\frac{x+180}{s}\\ \Rightarrow s= \frac{x+180}{20}---(ii)\)
From (i) and (ii)
\(\frac{x+140}{18}=\frac{x+180}{20}\\ 20x+2800=18x+3240\\ 2x=440\\ x=220\)
From (i). \(s=\frac{220+140}{18}=20\:mps\)
So, value of speed in Kmph will be \(=20\times \frac{18}{5}=72\:kmph\)
Last updated on Jun 12, 2025
-> SBI Clerk Mains Scorecard has been released on the Official website and candidates can also check the category-wise and state-wise SBI Clerk Cut Off Marks to check their performance.
-> The SBI Clerk Mains Result was released on 11th June 2025 for the exam held on 10th and 12th April 2025. Earlier, the Prelims exam was held on 22nd, 27th, 28th February and 1st March 2025.
-> Candidates can check the SBI Clerk Mains Exam Analysis for 10th April 2025 from the following Link.
-> The SBI Clerk 2025 Notification was released for 14,191 vacancies.
-> Graduates in any discipline are eligible for this post.
-> The selection process includes Prelims, Mains Exam, and a Language Test.
-> Attempt All India Rank Mega Live Test (Get your All India Live Rank), valid till 21st February 2025, 9 p.m.
-> Candidates must attempt the SBI Clerk mock tests to improve their performance. The SBI Clerk previous year question paper also help the candidates to check their performance.