Question
Download Solution PDFA three phase 4-pole induction motor runs at a speed of 1440 rpm on 500 V, 50 Hz mains. The shaft power developed by the motor is 20.3 HP. The rotational losses are 2.23 HP. Assuming no copper losses, the motor efficiency is
(Assume 1 HP = 735.5 W)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPower flow in induction motor
The efficiency of the motor is:
where, Pout = Shaft output
Losses = Rotational loss + Copper loss
If the copper loss is neglected, then losses are only due to rotational loss.
Calculation
Given, Pout = 20.3 HP = 20.3 × 735.5 = 14930.65 W = 14.93 kW
Losses = 2.23 HP = 1640.16 = 1.64 kW
η = 90.1%
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