Question
Download Solution PDFA student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many sums did he solve correctly?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Total sums attempted = 48
A student got twice as many sums wrong as he got right.
Calculation:
Let the number of sums solved correctly be x.
Number of sums solved wrong = 2x
Total sums attempted = x + 2x = 48
⇒ x + 2x = 48
⇒ 3x = 48
⇒ x = 48 / 3
⇒ x = 16
The number of sums solved correctly is 16.
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