Question
Download Solution PDFA solution contains three components A, B and C, 0.2 mole each, then sum of their mole fractions is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- The total number of moles of a compound divided by the total number of moles of all constituents gives us mole fraction.
- Mathematically, it can be expressed as:
\({X_1} = \;\frac{{no.\;of\;moles\;of\;sustance\;1}}{{total\;number\;of\;moles\;in\;the\;solution}}\)
Calculate Mole Fractions
For each component (A, B, C), the mole fraction \(X\) is calculated as:
\( X_{\text{A}} = \frac{\text{moles of A}}{\text{total moles}} = \frac{0.2}{0.6} = \frac{1}{3} \)
\( X_{\text{B}} = \frac{\text{moles of B}}{\text{total moles}} = \frac{0.2}{0.6} = \frac{1}{3}\)
\( X_{\text{C}} = \frac{\text{moles of C}}{\text{total moles}} = \frac{0.2}{0.6} = \frac{1}{3} \)
Sum of all mole fraction of all = 1/3 +1/3 + 1/3 = 1
- The total mole fraction of a solution always adds up to 1.
\(\sum {X_i = 1} \)
Mole fraction unit is very useful in relating some physical properties of solutions, says vapour pressure with the concentration of the solution and quite useful in describing the calculations involving gas mixtures.
Formula -
Mole Fraction = Moles of one component / Total moles of all component
XA+XB+XC = (NA/ NA+NB+NC) + (NB/ NA+NB+NC) + (NC/ NA+NB+NC) = 1
Last updated on Jun 6, 2025
-> The HTET TGT Applciation Portal will reopen on 1st June 2025 and close on 5th June 2025.
-> HTET Exam Date is out. HTET TGT Exam will be conducted on 26th and 27th July 2025
-> Candidates with a bachelor's degree and B.Ed. or equivalent qualification can apply for this recruitment.
-> The validity duration of certificates pertaining to passing Haryana TET has been extended for a lifetime.
-> Enhance your exam preparation with the HTET Previous Year Papers.