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A shunt generator has an induced e.m.f. of 224 V. When supplying a load, the terminal voltage falls to 204 V. The armature and shunt field resistances are 0.05 Ω and 20 Ω, respectively. The load current, neglecting the armature reaction, is

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  1. 376.0 A
  2. 389.8 A
  3. 400.0 A
  4. 410.2 A

Answer (Detailed Solution Below)

Option 2 : 389.8 A
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Generator induced emf Eg = 224 V

Terminal voltage V = 204 V

Field resistance Rf = 20 Ω

Field current 

Armature resistance, Ra = 0.05 Ω

Armature drop = 224 – 204 = 20 V

Armature current 

Load current IL = Ia – If = 400 – 10.2 = 389.8 A

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