Question
Download Solution PDFA policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at the speed of 10 km/h and 8 km/h, respectively. The distance (in km) run by the thief before he is nabbed by the policeman is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Distance between policeman and thief in the starting = 1250 m
Speed of policeman = 10 km/hr
Speed of thief = 8 km/hr
Concept: /Formula:
If the speed of a policeman and thief is x km/hr and y km/hr, then
Relative speed, if same directions = (x – y) km/hr
Distance between them after n hrs = (x – y) × n
1 km/hr = 5/18 m/sec
1 min = 60 sec
Calculation:
Distance between policeman and thief in starting = 1250 m
Relative speed of policeman and thief, if same directions = (10 – 8) = 2 × (5/18) = (5/9) m/sec
Time is taken by a policeman to cover the gap = 1250/(5/9)
= 2250 sec
The distance (in km) run by the thief before he is nabbed by the policeman = 8 × 2250/3600
= 5 km
The distance (in km) run by the thief before he is nabbed by the policeman is 5 km.
Last updated on Jul 9, 2025
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