A man borrowed ₹15,400 at 15% per annum compound interest. At the end of every year, he pays ₹2,500 as part repayment. How much (in ₹) does he still owe after three such instalments?

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MPPGCL JE Electrical 28 April 2023 Shift 1 Official Paper
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  1. 14,740.225
  2. 14,870.725
  3. 14,650.525
  4. 14,900.252

Answer (Detailed Solution Below)

Option 1 : 14,740.225
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MPPGCL JE Electrical Full Test 1
100 Qs. 100 Marks 120 Mins

Detailed Solution

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Given:

Principal (P) = ₹15,400

Rate of interest (r) = 15% per annum

Annual installment = ₹2,500

Number of years = 3

Formula used:

Amount after 1 year = P(1 + r/100) - installment

Repeat the process for subsequent years.

Calculation:

After 1st year:

⇒ A = 15,400 × (1 + 15/100) - 2,500

⇒ = 15,400 × 1.15 - 2,500

⇒ = 17,710 - 2,500 = ₹15,210

After 2nd year:

⇒ A = 15,210 × 1.15 - 2,500

⇒ = 17,491.50 - 2,500 = ₹14,991.50

After 3rd year:

⇒ A = 14,991.50 × 1.15 - 2,500

⇒ = 17,240.225 - 2,500

⇒ = ₹14,740.225

∴ The man still owes ₹14,740.225 after three years.

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