A concave mirror produces a three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Which option describes the image currently?

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ALP CBT 2 Physics and Maths Previous Paper 5 (Held On: 22 Jan 2019 Shift 2)
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  1. An inverted image is formed at a distance of 20 cm in front of the given concave mirror.
  2. An erect image is formed at a distance of 30 cm in front of the given concave mirror
  3. An inverted image is formed at a distance of 30 cm in front of the given concave mirror
  4. An erect image is formed at a distance of 20 cm in front of the given concave mirror

Answer (Detailed Solution Below)

Option 3 : An inverted image is formed at a distance of 30 cm in front of the given concave mirror
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Detailed Solution

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CONCEPT:

  • Concave mirror: If the inner surface of the spherical mirror is the reflecting surface, then it is called a concave mirror. It is also called a focusing mirror/converging mirror.
    • The size of the image produced by these mirrors can be larger or smaller than the object, depending upon the distance of the object from the mirror.
    • The concave mirror can form both real as well as virtual images of any object.
  • Mirror formula: The expression which shows the relation between object distance (u)image distance (v), and focal length (f) is called mirror formula.

\(\frac{1}{v} + \frac{1}{u} = \frac{1}{f}\)

Linear magnification (m):

  • It is defined as the ratio of the height of the image (hi) to the height of the object (ho).

\(m = \frac{{{h_i}}}{{{h_o}}}\)

  • The ratio of image distance to the object distance is called linear magnification.

\(m = \frac{{image\;distance\;\left( v \right)}}{{object\;distance\;\left( u \right)}} = - \frac{v}{u}\)

CALCULATION:

Given - m = 3 and object distance (u) = - 10 cm

  • The ratio of image distance to the object distance is called linear magnification.

\(⇒ m = \frac{{image\;distance\;\left( v \right)}}{{object\;distance\;\left( u \right)}} = - \frac{v}{u}\)

\(⇒ 3 = -\frac{v}{-10}\)

⇒ m = -30 cm

  • Here magnification is greater than 1, which means the image formed is enlarged, therefore an inverted image is formed at a distance of 30 cm in front of the given concave mirror. Therefore option 3 is correct.
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