A bomb at rest explodes into a large number of tiny fragments. The total momentum of all the fragments

CONCEPT:

Linear momentum

• It is defined as the product of the mass of an object, m, and its velocity, v. It, is a vector quantity.​

​⇒ P = mv

Conservation of momentum

• If the force applied to the system of particles is zero, then the total momentum of the system of particles will remain conserved.

\(\Rightarrow P_{1}+P_{2}+P_{3}+...+P_{n}=constant\)

CALCULATION:

Initially, the bomb is at rest.

• So total momentum of the bomb before explosion,

\(\Rightarrow P=mv\)

\(\Rightarrow P=m\times0\)

\(\Rightarrow P=0\)     -----(1)

• Since there is no external force that will apply to the particles during the explosion, so total momentum before and the after explosion will remain conserve.
• Since the total momentum before the explosion is zero, so the total momentum after the collision will also be zero. Hence, option 1 is correct.