Question
Download Solution PDFA block weighing 981 N is resting on a horizontal surface. The coefficient of friction between the block and the horizontal surface is μ = 0.2. A vertical cable attached to the block provides partial support as shown. A man can pull horizontally with a force of 100 N. What will be the tension, T (in N) in the cable if the man is just able to move the block to the right?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Number of vertical forces:
∑Fy = T + RN - W = 0
Static friction force is given as,
Fs = μRN
Calculation:
Given:
W = 981 N, μ = 0.2, Fs = 100 N
Normal reaction:
\(\Rightarrow {R_N} = \frac{{100}}{{0.2}} = 500~N\)
Tension T
⇒ T = 981 - 500 = 481 N
Last updated on Apr 14, 2023
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