A 5 KVA transformer has a turn ratio of N₁/N₂ 10. The impedance of the primary winding is 3 + j 5 ohms while that of secondary winding is 0.5 + j 0.8 ohms. The impedance of the transformer when referred to the primary will be

The correct answer is option 

Concept:

The impedance of the primary winding is Z₁

The impedance of the secondary winding is Z₂

The total impedance of the transformer referred to primary

Z = Z₁ + Z₂ ( \(N_1 \over N_2\) )²

Calculation:

Given

\(N_1 \over N_2\) = 10

Z₁ =   3 + j 5 Ω 

Z₂ = 0.5 + j 0.8 Ω

Z = Z1 + Z2 ( \(N_1 \over N_2\) )²

=  3 + j 5 + (0.5 + j 0.8) × 10²

= 53·0 + j 85 Ω