Question
Download Solution PDFA 338-m-long train is travelling at 60 km/h. It crosses a man, travelling in the same direction, in 39 seconds. What is the speed (in m/sec) of the man?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Distance = 338 m
Speed of train = 60 km/hr
Time = 39 seconds
Formula used:
Speed = Distance/Time
Calculation:
Le the speed of a ma be x m/s
Speed of train = 60 km/hr
⇒ (60 × 5/18) = 50/3 m/s
Relative speed = (50/3 – x) [It travels in the same direction]
Now,
Speed = Distance/Time
⇒ (50/3 – x) = 338/39
⇒ (50/3 – x) × 39 = 338
⇒ 50/3 × 39 – 39x = 338
⇒ 650 – 39x = 338
⇒ 39x = (650 – 338)
⇒ 39x = 312
⇒ x = 8 m/s
∴ The required speed of the man is 8 m/s
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