A 2 HP water pump runs for 10 minutes. The electrical energy consumed by it is

  1. 8.952 × 105 J
  2. 8.952 × 106 J
  3. 8.952 × 104 J
  4. 8.952 × 107 J

Answer (Detailed Solution Below)

Option 1 : 8.952 × 105 J
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Electric charges and coulomb's law (Basic)
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Detailed Solution

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CONCEPT:

  • Power: The rate of work done is called power.
    • It is denoted by P.
    • Mathematically it is written as

\(Power\;\left( P \right) = \frac{{\;W}}{{t}}\)

CALCULATION:

Given - Power (P) = 2 HP = 1492 J/sec and time (t) = 10 minutes = 600 sec

  • The electrical energy consumed by it is 

⇒ W = Pt = 1492 × 600 = 895200 J = 8.952 × 105 J

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