7 is added to a certain number and the sum is multiplied by 5. The product is then divided by 3 and 4 is subtracted from the quotient. If the result comes to 16, then what is the original number?

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SSC CGL 2022 Tier-I Official Paper (Held On : 08 Dec 2022 Shift 3)
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  1. 3
  2. 1
  3. 5
  4. 4

Answer (Detailed Solution Below)

Option 3 : 5
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Detailed Solution

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Given:

7 is added to a certain number and the sum is multiplied by 5. The product is then divided by 3 and 4 is subtracted from the quotient. If the result comes to 16.

Concept used:

Let the number be = x

7 is added to a certain number and the sum is multiplied by 5 ⇒ (x +7) × 5

The product is then divided by 3 and 4 is subtracted from the quotient and the result is 16 ⇒ \(5(x+7)\over 3\) - 4 = 16

Calculation:

\(5(x+7)\over 3\)- 4 = 16

⇒ 5(x + 7) - 12 = 16 × 3 

⇒ 5x + 35 - 12 = 48 

⇒ 5x + 23 = 48 

x = 5

Hence, the original number is 5.

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