5 resistors of 10 Ω are connected in parallel. A current of 1 A flows through each of them. What will be the current through each of them if they are connected in series?

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ALP CBT 2 Electronic Mechanic Previous Paper: Held on 21 Jan 2019 Shift 1

Answer 1

5 Resistors of 10 Ω connected in parallel with 1 A flowing through each of them is as shown:

F1 Shubham Madhuri 13.08.2021 D1

Since the voltage source is parallel to the resistance, the voltage across each resistance will be:

V_10 Ω = 10 × 1 V

V10 Ω = 10 V

Now, when the resistors are connected in series, the circuit will be:

F1 Shubham Madhuri 13.08.2021 D2

The series combination of these resistances will give a total resistance of:

R_total = 10 + 10 + 10 + 10 + 10 Ω

R_total = 50 Ω

The current through resistors in series will be equal, i.e.

\(I=\frac{10}{50}A\)

I = 0.2 A

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