ABCD Parameters MCQ Quiz in తెలుగు - Objective Question with Answer for ABCD Parameters - ముఫ్త్ [PDF] డౌన్‌లోడ్ కరెన్

Concept:

There are four variables V1, V2, I1, and I2 in a two-port network as shown in the figure

From the ABCD parameters matrix, we get the following equations.

V1 = A V2 – B I2

I1 = C V2 - D I2

Calculation:

For two-port Network and parameters:

      ---(1)

Now, for ABCD parameters

V₁ = AV₂ – BI₂

I₁ = CV₁ – DI₂

From equation (1)

Concept:

There are four variables V1, V2, I1, and I2 in a two-port network as shown in the figure

From the ABCD parameters matrix, we get the following equations.

V1 = A V2 – B I2

I1 = C V2 - D I2

Calculation:

For two-port Network and parameters:

      ---(1)

Now, for ABCD parameters

V₁ = AV₂ – BI₂

I₁ = CV₁ – DI₂

From equation (1)

Concept:

ABCD parameters are defined as:

V1 = A V2 – B I2

I1 = C V2 – D I2

Application:

With A = 1, B = -j, C = 1 and D = 1 - j, the ABCD equations can be written as:

V1 = V2 - (- j) I2   ---(1)

I1 = V2 – (1 - j) I2   ---(2)

The given two-port network is redrawn as:

Z₁ can be obtained by short-circuiting the output, i.e.

Applying KVL at the output, we get

V₁ + I₂Z₁ = 0

V₁ = -I₂Z₁

Comparing this with the given ABCD matrix of Equation (1), we get:

B = Z₁ = - j

∴ Z₁ = - j Ω 

Concept:

ABCD parameter for any two-port network given below is expressed as:

Calculation:

For I₂ = 0,

Applying voltage division across Z₃:

 ---- (1)

Applying Ohms Law across Z₃

 ---- (2)

For V₂ = 0,

Applying current division:

 ----(3)

Apply KVL,

 ---- (4)

Form 1, 2, 3 & 4

Concept:

We know that the ABCD parameter of transmission line 

For symmetrical network:

A = D

For reciprocity network:

AD – BC

Analysis:

For symmetrical network A = D = 3

For bilateral AD – BC = 1

9 – C = 1

C = 8

Conditions of reciprocity and symmetry in terms of different two-port parameters are:

h-parameter: (Hybrid parameter)

For a two-port Network:

V₁ = h₁₁I₁ + h₁₂V₂

I₂ = h₂₁I₁ + h₂₂V₂

T-paraemeter (ABCD Parameter):

V₁ = AV₂ – BI₂

I₁ = CV₂ – DI₂

Two port Network conversion table:

Where

ΔZ = Z₁₁Z₂₂ – Z₁₂Z₂₁

Δh = h₁₁h₂₂ – h₂₁h₁₂

ΔY = Y₁₁Y₂₂ – Y₁₂Y₂₁

ΔT = AD - BC

Explanation:

From the table

Notes:

Concept:

Transmission or ABCD parameters

General two-port network and Transmission parameters two-port network is shown below.

Transmission 2 port network

The direction of I₂ is opposite to the standard form so it is taken as negative.

Transmission parameters are defined as:

V₁ and I₁ are dependent and V₂ and I₂ are independent.

Calculation:

From the ABCD parameters matrix, we get the following equations.

V₁ = A V₂ – B I₂

I₁ = C V₂ - D I₂

To calculate B we have to make V₂ = 0.

Element in parallel to the short circuit is redundant.

Apply KVL in the loop

- V1 – j2 × I2 = 0

B =  j2 Ω 

Concept:

ABCD Parameters:

ABCD parameters relate the variables at the input port to those at the output port.

V1 = AV2 - BI2

I1 = CV2 - DI2

With output open-circuited, i.e. I2 = 0, the two parameters we get are:

A = Reverse voltage ratio, as it is the ratio of output voltage and the input voltage

C = Transfer admittance, as it is the ratio of current to the voltage

With the input short-circuited, i.e. V1 = 0, the two parameters we get are:

Analysis:

And 

Input Impedance:

∴ Input Impedance = 

(4) is correct.

Concept:

The general ABCD parameter for the two-port network can be given by:

But if we reverse the direction of I₁ and I₂ then:

Application:

Given:

At the output side, we can write:

V₂ = -5 I₄       ---(1)

V₁ = -5 I₃         ---(2)

Putting I₃ and I₄ in Equation (1) and (2), we get:

Now make V₂ = 0 by short-circuiting at the output port.

V₁ = -5 I₁ – 5 I₂       ----(3)

Also V₁ = 10 I₂        ---(4)

From (3) and (4)

10 I₂ = -5 I₁ – 5 I₂

15 I₂ = -5 I₁

I₁ = -3 I₂      ---(5)

Using Equation (4), we get:

Using Equation (5), we get:

Given that N₁ : N₂ = 4 : 1

But here