Z Parameters MCQ Quiz in தமிழ் - Objective Question with Answer for Z Parameters - இலவச PDF ஐப் பதிவிறக்கவும்

Last updated on Mar 18, 2025

பெறு Z Parameters பதில்கள் மற்றும் விரிவான தீர்வுகளுடன் கூடிய பல தேர்வு கேள்விகள் (MCQ வினாடிவினா). இவற்றை இலவசமாகப் பதிவிறக்கவும் Z Parameters MCQ வினாடி வினா Pdf மற்றும் வங்கி, SSC, ரயில்வே, UPSC, மாநில PSC போன்ற உங்களின் வரவிருக்கும் தேர்வுகளுக்குத் தயாராகுங்கள்.

Latest Z Parameters MCQ Objective Questions

Top Z Parameters MCQ Objective Questions

Z Parameters Question 1:

For the single-element two-port network in the figure, z11 is:

  1. 0
  2. 10
  3. 4
  4. Undefined

Answer (Detailed Solution Below)

Option 4 : Undefined

Z Parameters Question 1 Detailed Solution

Concept:

The z parameters of a two-port network is defined as:

V1 = z11 I1 + z12 I2

V2 = z21 I1 + z22 I2

Calculation:

z11 and z21 parameters are calculated by open circuiting the output (i.e. I2 = 0)

The circuit given will be redrawn as:

With i2 = 0

From the above, we see that I1 = 0

So, 

Z Parameters Question 2:

For the circuit shown. If

The value of I1 is _____ A

Answer (Detailed Solution Below) 0.78 - 0.82

Z Parameters Question 2 Detailed Solution

V1 = 10 I1 - 6 I2        ____ (1)

V2 = -4 I1 + 12 I2         _____ (2)

V2 = -10 I2        ____ (3)

Convert the current source to voltage source.

:

12 - 6 I1 - V1 = 0

V1 = 12 - 6 I1 ____ (4)

Substitute equation (3) and (4) in (1) and (2)

12 - 6I1 = 10 I1 - 6 I2

12 = 16 I1 - 6 I2       ____ (5)

-10 I2 = -4 I1 + 12 I2

0 = -4 I1 + 22 I2      ____(6)

From 5 and 6

I1 = 0.8049 A

I2 = 0.1463 A

Z Parameters Question 3:

Find the Z-parameters for the following network.

Answer (Detailed Solution Below)

Option 3 :

Z Parameters Question 3 Detailed Solution

Z Parameters Question 4:

In the two port network shown below, if V1 & V2 are expressed in terms of I1 & I2 using the expression V1 = Z11I1 + Z12I2 & V= Z21I1 + Z22I2 then Z11 and Z22 are called

  1. Open circuit impedance
  2. Short circuit admittance
  3. Trans impedance
  4. Trans conductance

Answer (Detailed Solution Below)

Option 1 : Open circuit impedance

Z Parameters Question 4 Detailed Solution

Z-parameters:

Z-parameters are also known as the Open-Circuit impedance parameters as they are calculated under open-circuit conditions, i.e. at I1 = 0 and I2 = 0, In the matrix form, they are expressed as:

V1 = z11I1 + z12I2

V2 = z21I1 + z22I2

With the input open-circuited, i.e. I1 = 0, the two parameters obtained are:

With the output open-circuited, i.e. I2 = 0, the two parameters we obtain are:

Z Parameters Question 5:

Consider the following statements for a symmetrical T section:

1. Z11 and Z22 are equal.

2. Z12 and Z21 are equal.

3. Z11 and Z12 are equal.

4. Z21 and Z22 are equal.

Which of the above statements are correct?

  1. 1 and 2 only
  2. 2 and 3 only
  3. 3 and 4 only
  4. 1, 2, 3 and 4

Answer (Detailed Solution Below)

Option 1 : 1 and 2 only

Z Parameters Question 5 Detailed Solution

Concept:

The condition in the symmetrical T network is that the total series arm impedance and shunt arm impedance must be z1 and z2 respectively.

Analysis:

We know;

Z-parameter;

V1 = Z11 I1 + Z12 I2       ---(1)

V2  = Z21 I1 + Z22 I2      ---(2)

        ---(3)

       ---(4)

From (1), (2), (3), (4)

 

 

∴Z21 = Z12

Z11 = Z22

Z Parameters Question 6:

The value of resistance seen by voltage source shown below is _______ Ohms.

Answer (Detailed Solution Below)

Option 3 :

Z Parameters Question 6 Detailed Solution

Concept:

Z-parameters are also known as the Open-Circuit impedance parameters as they are calculated under open-circuit conditions, i.e. at I1 = 0 and I2 = 0, In the matrix form, they are expressed as:

V1 = z11I1 + z12I2

V2 = z21I1 + z22I2

Calculation:

From Z-parameters:

V1 = 4I1 + I2       ---(1)

V2 = I1 + 2I2       ---(2)

From (2):

– I2 = I1 + 2I2

3I2 = -I1

    ---(3)

From (1):

∴ Resistance seen by the voltage source is:

Z Parameters Question 7:

Consider the circuit as shown below. The Value of V2/V1 is

  1. 1
  2. 2

Answer (Detailed Solution Below)

Option 3 :

Z Parameters Question 7 Detailed Solution

Apply nodal analysis at V2,

      ----(1)

     ----(2)

By solving equations (1) and (2)

⇒ 2V2 - V1 = α (V1 - V)

Z Parameters Question 8:

For the circuit shown below, the impedance parameter matrix [Z] is

Answer (Detailed Solution Below)

Option 3 :

Z Parameters Question 8 Detailed Solution

Calculation:

 

Applying KCL at VA

 

V1 - VA + 2V2 - VA = 0

V1 + 2V2 = 2VA      ---(1)

I2 = V2 - VA

I2 = V2 – 0.5 V1 – V2

0.5 V1 = - I2

V1 = 0I­1 – 2I ---- (1)

Applying KCL to find I1, we get

I1 = V1 + V1 - VA

= 2V1 – 0.5 V1 – V2

I1 = 1.5 V1 – V2

V2 = 1.5 V1 – I1

= 1.5(-2 I2) – I1

V2 = -3I2 – I1 ---- (2)

= -I1 – 3I2

∴ 

Z Parameters Question 9:

The z-parameter matrix  for the two-port network shown is.

Answer (Detailed Solution Below)

Option 1 :

Z Parameters Question 9 Detailed Solution

Concept:

Z parameters:

V1 = Z11 I1 + Z12 I2

V2 = Z21 I1 + Z22 I2

 is the input driving point impedance or open circuit input impedance

 is the open circuit transfer impedance from port 1 to port 2

is the open circuit transfer impedance from port 2 to port 1

 is the output driving point impedance or open circuit output impedance

Calculation:

Apply Nodal at A, we get:

   ---(1)

With I1 = 0,

V2 = 2I2

Z22 = 2

With I2 = 0,

V2 = -2I1

Z21= -2

And from the figure we get:

Z Parameters Question 10:

For the given two-port network, what are the values of current I1 and I2?

  1. 2∠0° A, 1∠90° A
  2. 2∠0° A, 1∠0° A
  3. 2∠0° A, 1∠-90° A
  4. 2∠-90° A, 1∠-90° A

Answer (Detailed Solution Below)

Option 3 : 2∠0° A, 1∠-90° A

Z Parameters Question 10 Detailed Solution

Concept:

The z-parameter equations for a two-port network is given by:

V1 = z11 I1 + z12 I2

V2 = z21 I2 + z22 I2

Where the voltages and current can be in phasors as well.

Application:

V1 = 100 ∠0

And V2 = -10 I2

Where bold letter V/I represents the phasor voltage and current respectively.

Substituting V1 and V2 in the standard 2-port z-parameter equations, we get:

100 = 40 I1 + j20 I2      ---(1)

-10 I2 = j30 I1 + 50 I2

-60 I2 = j30 I1

Substituting I2 in equation (1), we get:

⇒ 100 = 40 I1  + 10I1

I2 = 1∠-90° A

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